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7.6t=4.9t^2
We move all terms to the left:
7.6t-(4.9t^2)=0
We get rid of parentheses
-4.9t^2+7.6t=0
a = -4.9; b = 7.6; c = 0;
Δ = b2-4ac
Δ = 7.62-4·(-4.9)·0
Δ = 57.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7.6)-\sqrt{57.76}}{2*-4.9}=\frac{-7.6-\sqrt{57.76}}{-9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7.6)+\sqrt{57.76}}{2*-4.9}=\frac{-7.6+\sqrt{57.76}}{-9.8} $
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